[MEncoder-users] mencoder output
brbromo at gmail.com
Wed Mar 8 16:44:54 CET 2006
On 3/6/06, RC <rcooley at spamcop.net> wrote:
> > >>Right here mencoder is specifying that the video should be scaled to
> > >>match the original 1.33:1 aspect ratio. If you
> > >>don't want that to happen you can either:
> > No, I don't want to match the original aspect ratio, because the
> > cropped image would be stretched.
> You've completely misunderstood. It's scaling to the correct aspect
> BEFORE cropping/scaling.
Cropping is made on the sampled image, not on the
scaled-to-correct-aspect-ratio image, right?
Encoding is made using the sampled image, too. Right?
I suppose that the -vf scale filter is applied on the sampled image,
correcting the specified scale ratio to take into account the image
So what's the reason of this prescaling? Who needs the
> I think you're just making this far more difficult for yourself. If you
> want the correct aspect ratio set in the output file, use "-lavcopts
I'm using xvid. Does it work with xvid, too?
> If you want square pixels (for players like that don't
> support an aspect in MPEG-4 video or in an AVI) then just use "-vf
I don't care about such players. I don't want *square pixels* (i.e.
same display and sampled width and height in the encoded movie). I
just want squares to keep their aspect ratio.
I'm getting this result with dsize=newAR, where newAR =
(w'/h')/(w/h)*(oldAR). But this *seems* mencoder default behaviour. Is
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