Hi When we designed the pts->dts reorder algorithm we considered arbitrary frame reorderings, but there was something we missed, that are mixes of frame and field pictures, like: i1 p2 P3 p4 P5 p7 P8 (lower case is a field, upper is a frame) PTS 2 3 4 6 7 9 10 DTS 0 1 2 4 5 7 8 As you can see no reordering of PTS can result in the DTS values. The reason why this fails is (if my brain still works at 5:30am) that frame pictures contain 2 fields and thus would have to be counted like 2 besides that they would really need 2 pts. I suspect some solution based on dummy 0byte packets with the missing pts after each frame might solve this, but i must think more about this ... -- Michael GnuPG fingerprint: 9FF2128B147EF6730BADF133611EC787040B0FAB I do not agree with what you have to say, but I'll defend to the death your right to say it. -- Voltaire