[MPlayer-users] newbie question: bitrate

[Stefan Lange]

Yan Seiner wrote:
> [Automatic answer: RTFM (read DOCS, FAQ), also read DOCS/bugreports.html]
> I am a complete newbie at this, so excuse me if this is a dumb Q.
> 
> Could someone explain bitrate to me?   Here's what I'm trying to do:
> 

bitrate is the bandwidth used by the codec per unit of time, i.e. 
800kbit/s means that the video needs 800kbit per second, or 
800kbit/s*3600s=2 880 000 bits for one hour (approx. 350 MB)



> Take a DVD or or videocassette, and rip it to a hard disk in a format
> suitable for a small TV.
> 
> I've been playing with a resolution of 328x242 (OK on an NTSC TC), but I
> still get files of about 1.2 GB, which seems enormously large, so I'm
> guessing that I need to provide a bitrate suitable for that resolution.
> 
> What exactly is a bitrate, and how do I go about calculating a bitrate
> suitable for such a low resolution?
> 

Please read DOCS/tech/encoding-tips.txt, it will probably cover all your 
questions.


> Note that I am not interested in stuffing a movie onto a CD; I'm not
> really concerned about how large the final product is.  I want it to be
> as small as the resolution warrants.
> 
> Thanks,
> 
> --Yan
> 
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