[MEncoder-users] Bits per block

[Grozdan Nikolov]

On Thursday 12 July 2007 15:33, Federico Zema wrote:
> On Thu, 12 Jul 2007, Grozdan Nikolov wrote:
> >                    videobitrate * 1000
> > bpb = --------------------------------------
> >           fps * ((width * height) / (16 * 16))
> >
> > And here's where I get a bit confused. He talks about 2 digit values as
> > outcome (40 and 50 bpb) but when I calculate the bpb value for a 640x480
> > movie with a 25 FPS value and 900 kbps as bitrate, I get huge values as
> > outcome, eg
> >
> > echo $(($((900*1000))/25*$((640*480))/$((16*16))))
> >
> > and I get 43200000 as outcome. Only if I divide this outcome with 1000000
> > I get a two digits value (43 in this case)
> >
> > So my question is am I the one who's doing something wrong here or is the
> > above formula wrong?
>
> Hi,
>  you are missing a couple of double parenthesis:
>
> echo $(($((900*1000))/$((25*$((640*480))/$((16*16))))))
> 30

aahhh, I see, thanks for pointing out ;)

>
>  Cheers
>  Federico
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