[FFmpeg-user] psnr range

[Nicolas George]

Carl Eugen Hoyos (12019-06-26):
> The source code contains the following line in vf_psnr.c:
> return 10.0 * log10(pow_2(max) / (mse / nb_frames))
> so a likely range is 0-100

You are reading the formula upside down: x/max would have a range [0;1]
(possibly later converted to a percentage), but max/x has range [1;+∞].
And indeed, +∞ is a possible value for lossless encoding.

Then the logarithm turns the range to [0:+∞].

Regards,

-- 
  Nicolas George
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