[FFmpeg-user] Conversion from WMV to M2V - Lost Frame Problem

Andrew Arthur ikrananka at hotmail.com
Mon Dec 1 17:14:24 CET 2014


> -----Original Message-----
> From: ffmpeg-user-bounces at ffmpeg.org [mailto:ffmpeg-user-
> bounces at ffmpeg.org] On Behalf Of Carl Eugen Hoyos
> Sent: November-18-14 3:53 PM
> To: ffmpeg-user at ffmpeg.org
> Subject: Re: [FFmpeg-user] Conversion from WMV to M2V - Lost Frame
> Problem
> 
> Andrew Arthur <ikrananka <at> hotmail.com> writes:
> 
> > However, the output from ffmpeg shows in VirtualDub as being 1036
> > frames
> 
> Please run:
> $ ffmpeg -i output.m2v -f null -
> One of the last lines of the console output sill show you the actual
> number of frames in the m2v file.
> 
> If you don't believe the number the following command will output every
> single frame of your video as a raw mpeg2video file.
> $ ffmpeg -i output.m2v -vcodec copy -f image2 raw%4d.m2v
> 
> The following will output a jpg for every single frame:
> $ ffmpeg -i output.m2v out%4d.jpg
> 

Thanks Carl.  Looks like the frame count using the mpeg plug-in for
Virtualdub is wrong.  Using the commands you gave above I get the correct
frame count.  I also verified this with Adobe Premiere which concurred with
the ffmpeg frame count.



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