[FFmpeg-user] using atempo in PHP

[Jevlachov D.]

It was wrong path to ffmpeg.
That's what I have now:

$path = '/usr/bin/ffmpeg';
$source = 'Help_-_The_Beatles.mp3';
$target = 'converted.mp3';
$exec_string = $path.' -i '.escapeshellarg($source).' atempo=1.5
'.escapeshellarg($target).'  2>ffmpeg.log &';
echo exec($exec_string);

It gives me: Unable to find a suitable output format for 'atempo=1.5'
I guess something is wrong with $target. Can't figure out what.
What I need is just simple speedup (atempo) of given mp3.

On Mon, Oct 15, 2012 at 6:39 PM, Reindl Harald <h.reindl at thelounge.net>wrote:

>
>
> Am 15.10.2012 13:18, schrieb Tom Evans:
> > On Mon, Oct 15, 2012 at 11:08 AM, Jevlachov D. <jevlachov at gmail.com>
> wrote:
> >> Can't figure out how to use atempo properly.
> >>
> >> part of the script looks like this:
> >>
> >> echo shell_exec("ffmpeg -y -i original.mp3 -filter:a
> >> atempo=1.5 converted.mp3 2>ffmpeg.log &");
> >>
> >> (example code taken from here
> >>
> http://ffmpeg.org/trac/ffmpeg/wiki/Using%20FFmpeg%20from%20PHP%20scripts)
> >>
> >> It returns "sh: line 1: converted.mp3: command not found" in log file.
> >>
> >> Thanks!
> >
> > That sounds more like you can't figure out how to use PHP properly
> > tbh. Put another way, you're not even running ffmpeg yet..
> >
> > Is there not a PHP command that allows you to specify the command and
> > arguments as an array, bypassing all that shell nonsense?
>
>
>


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