[FFmpeg-user] convert .dxa file format

[Pedram Hayati]

Hi

I got .dxa video file format from a video surveillance camera. trying to 
whether compile or play this file. so far I got this error using ffmpeg:

ffmpeg -i file.dxa
FFmpeg version UNKNOWN, Copyright (c) 2000-2011 the FFmpeg developers
   built on Mar 22 2011 23:16:52 with gcc 4.4.3
   configuration: --enable-gpl --enable-version3 --enable-nonfree 
--enable-postproc --enable-libfaac --enable-libopencore-amrnb 
--enable-libopencore-amrwb --enable-libtheora --enable-libvorbis 
--enable-libx264 --enable-libxvid --enable-x11grab
   libavutil    50. 40. 0 / 50. 40. 0
   libavcodec   52.114. 0 / 52.114. 0
   libavformat  52.103. 0 / 52.103. 0
   libavdevice  52.  3. 0 / 52.  3. 0
   libavfilter   1. 76. 0 /  1. 76. 0
   libswscale    0. 12. 0 /  0. 12. 0
   libpostproc  51.  2. 0 / 51.  2. 0
file.dxa: Invalid data found when processing input

anyway to get around this file? any comments?

hope some guys play with dxa before.

Cheers,
Pedi