[FFmpeg-devel] [PATCH 2/2] avformat/mxfdec: use binary search in mxf_absolute_bodysid_offset

Marton Balint cus at passwd.hu
Fri Mar 9 02:28:24 EET 2018



On Mon, 5 Mar 2018, Marton Balint wrote:

>
>
> On Sun, 4 Mar 2018, Tomas Härdin wrote:
>
>> tor 2018-03-01 klockan 22:41 +0100 skrev Marton Balint:
>>> > Signed-off-by: Marton Balint <cus at passwd.hu>
>>> ---
>>>  libavformat/mxfdec.c | 22 ++++++++++++++--------
>>>  1 file changed, 14 insertions(+), 8 deletions(-)
>>> 
>>> diff --git a/libavformat/mxfdec.c b/libavformat/mxfdec.c
>>> index d4291f5dc7..70091e0dc9 100644
>>> --- a/libavformat/mxfdec.c
>>> +++ b/libavformat/mxfdec.c
>>> @@ -1347,24 +1347,30 @@ static int 
> mxf_get_sorted_table_segments(MXFContext *mxf, int *nb_sorted_segment
>>>   */
>>>  static int mxf_absolute_bodysid_offset(MXFContext *mxf, int body_sid, 
> int64_t offset, int64_t *offset_out)
>>>  {
>>> -    int x;
>>>      MXFPartition *last_p = NULL;
>>> +    int a, b, m, m0;
>>>  
>>>      if (offset < 0)
>>>          return AVERROR(EINVAL);
>>>  
>>> -    for (x = 0; x < mxf->partitions_count; x++) {
>>> -        MXFPartition *p = &mxf->partitions[x];
>>> +    a = -1;
>>
>> I've got a bad feeling about this -1
>
> There is an explicit check after the loop when we actually use the value 
> of 'a' to see if it remained -1 or not. Other than that using this 
> construct (a = -1, b = count) is also used in other places throughout the 
> codebase for binary search.
>
>>
>>> +    b = mxf->partitions_count;
>>>  
>>> -        if (p->body_sid != body_sid)
>>> -            continue;
>>> +    while (b - a > 1) {
>>> +        m0 = m = (a + b) >> 1;
>>
>> Could overflow with a specially crafted file. But I guess it would have
>> to be on the order of 1 TiB.
>
> I guess we could limit the number of partitions to INT_MAX / 2, although 
> it really needs a *huge* crafted file and parsing it would probably take 
> ages for the demuxer anyway...
>
>>
>> It also looks like this might behave incorrectly when a=-1, b=0
>
> That can't happen as the loop condition would be false in that case.
>

Will push this soon.

Regards,
Marton


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